Question

已知a/2=b/3≠0，求代数式5a-2b/a²-4b²×(a-2b)

Answer 1

设a=2k，b=3k，则有：
5a-2b/a²-4b²×(a-2b)
=(5a-2b)/(a+2b)(a-2b)×(a-2b)
=(5a-2b)/(a+2b)
=(10k-6k)/(2k+6k)
=4/8;
=1/2;

有帮助请记得好评，新问题请重新发帖提问，谢谢！！！(*^__^*) ……

追答

设a=2k，b=3k，则有：
5a-2b/a²-4b²×(a-2b)
=(5a-2b)/(a+2b)(a-2b)×(a-2b)
=(5a-2b)/(a+2b)
=(10k-6k)/(2k+6k)
=4/8;
=1/2;

有帮助请记得好评，新问题请重新发帖提问，谢谢！！！(*^__^*) ……

设a=2k，b=3k，则有：
5a-2b/a²-4b²×(a-2b)
=(5a-2b)/(a+2b)(a-2b)×(a-2b)
=(5a-2b)/(a+2b)
=(10k-6k)/(2k+6k)
=4/8;
=1/2;

有帮助请记得好评，新问题请重新发帖提问，谢谢！！！(*^__^*) ……