请教一道gre数学题目?
Afterpreparingtheresultsoftheirmeasurementoftheweightofchildrenthatparticipatedinthei...
After preparing the results of their measurement of the weight of children that participated in their pediatric study, Steph’s graduate assistant spilled coffee on their papers. If Steph is able to read that 50 lbs is the third standard deviation to the left of the mean, and 110 lbs also falls on a standard deviation, then which of the following could be the mean weight of the children in the study, assuming regular distribution?Indicate all possible values.
A80
B85
C86
D95
E100
题看不太懂 展开
A80
B85
C86
D95
E100
题看不太懂 展开
展开全部
在准备他们的孩子参加他们的儿科研究的重量测量结果,我的研究生助理把咖啡洒在他们的论文。如果我能读到50磅,是第三个标准差的平均左,和110磅也落在一个标准偏差,那么下面哪一个可能是本研究中的儿童的平均重量,假设均匀分布?显示所有可能的值。
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
选A,C. D
因为80-50=30 30÷3=10 而110=80+3×10
86-50=36 36+3=12 而110=86+12×2
95-50=45 45÷3=15 而110=95+15×1
剩下两个除不尽.。。。
因为80-50=30 30÷3=10 而110=80+3×10
86-50=36 36+3=12 而110=86+12×2
95-50=45 45÷3=15 而110=95+15×1
剩下两个除不尽.。。。
更多追问追答
追问
可是答案只有一个 95 我不太懂题意 你能解释下If Steph is able to read that 50 lbs is the third standard deviation to the left of the mean, and 110 lbs also falls on a standard deviation是什么意思吗
追答
如果Steph能够读出50磅是平均值向左的第三个标准差,而且110磅也落在标准差的点上
我的理解是这样的,设平均值为x,标准差为a
则x-3a=50,同时x+Na=110,其中满足N为整数,你看是不是这样。。但是答案为什么只有一个我没搞懂。。
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
The sales in July 1993 was around 7000.
The least monthly sales would be Feb and Mar 1993, which would be around 4500.
The percent increase, from 4500 to 7000, would be (7000-4500)÷4500=55.56%
The least monthly sales would be Feb and Mar 1993, which would be around 4500.
The percent increase, from 4500 to 7000, would be (7000-4500)÷4500=55.56%
追问
你确定你不是在开玩笑??
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
2015-06-04
展开全部
新东方在线论坛GRE专区有很多考过的同学互相帮助,可以去看看。
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询