因式分解(有过程)1.n^2(m-2)-n(2-m) 2.9(x+y)^2-4(x-y)^2 3.(x+y)^2-4(x+y-1)4.(x-1)(x-3)+1
3个回答
2012-01-02 · 知道合伙人教育行家
关注
展开全部
n^2(m-2)-n(2-m)
= n^2(m-2)+n(m-2)
=n(m-2)(n+1)
9(x+y)^2-4(x-y)^2
= [3(x+y)+2(x-y)][3(x+y)-2(x-y)]
= (5x+y)(x+5y)
(x+y)^2-4(x+y-1)
= (x+y)^2-4(x+y)+4
= (x+y-2)^2
(x-1)(x-3)+1
=(x-2+1)(x-2-1)+1
= (x-2)^2-1^2+1
=(x-2)^2
= n^2(m-2)+n(m-2)
=n(m-2)(n+1)
9(x+y)^2-4(x-y)^2
= [3(x+y)+2(x-y)][3(x+y)-2(x-y)]
= (5x+y)(x+5y)
(x+y)^2-4(x+y-1)
= (x+y)^2-4(x+y)+4
= (x+y-2)^2
(x-1)(x-3)+1
=(x-2+1)(x-2-1)+1
= (x-2)^2-1^2+1
=(x-2)^2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
,1,=(m-2)(n^2+n)
=n(m-2)(n+1)
2,=[3(x+y)+2(x-y)](3(x+y)-2(x-y)]
=(5x+y)(x+5y)
3,=(x+y)^2-4(x+y)+4
=(x+y-2)^2
4,=x^2-4x+3+1
=x^2-4x+4
=(x-2)^2
=n(m-2)(n+1)
2,=[3(x+y)+2(x-y)](3(x+y)-2(x-y)]
=(5x+y)(x+5y)
3,=(x+y)^2-4(x+y)+4
=(x+y-2)^2
4,=x^2-4x+3+1
=x^2-4x+4
=(x-2)^2
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询