Question

C语言程序运行结果不对，跟结构数组有关

#include<stdio.h>
struct Student
{char name[20];
char major[20];
int English;
int Maths;
int C;
int score;
}stu[5]={{"zhang","通信",98,88,79,0},{"li","网络",67,78,89,0},{"lin","物联网",93,68,85,0},{"sun","网络",98,93,95,0},{"min","通信",88,79,69,0}};

void main()
{
struct Student *p=stu;
struct Student count(struct Student stu[5]);
count(p);
}

struct Student count (struct Student stu[5])
{
int ave[2];
int num1[3];
int grades[3];
int i;
int socre[5];
for(i=0;i<5;i++)
{
stu[i].score=stu[i].English+stu[i].Maths+stu[i].C;
if(stu[i].major=="通信")
{num1[0]++;
grades[0]=grades[0]+stu[i].score;}
else if
(stu[i].major=="网络")
{num1[1]++;
grades[1]=grades[1]+stu[i].score;}
else if
(stu[i].major=="物联网")
{num1[2]++;
grades[2]=grades[2]+stu[i].score;}
ave[i]=grades[i]/num1[i];}
printf("通信专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[0],grades[0],ave[0]);
printf("网络专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[1],grades[1],ave[1]);
printf("物联网专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[2],grades[2],ave[2]);
printf("\n学生成绩输出如下:\n");
for(i=0;i<5;i++)
printf("姓名:%5s\t专业:%5s\t英语成绩:%d\t数学成绩:%d\tC语言成绩:%d\t总成绩:%d\n",stu[i].name,stu[i].major,stu[i].English,stu[i].Maths,stu[i].C,stu[i].score);

}

怎么修改呢~

Answer 1

c语言中判断两个字符串是否相同，用到字符串比较函数strcmp(),不能用==
所以把你程序中所用判断字符串相等的if函数改了即可,如：
struct Student count (struct Student stu[5])
{
int ave[3]; //改后
int num1[3];
int grades[3];
int i;
int socre[5];
for(i=0;i<5;i++)
{
stu[i].score=stu[i].English+stu[i].Maths+stu[i].C;
if(strcmp(stu[i].major,"通信")==0) // 改后是
{num1[0]++;
grades[0]=grades[0]+stu[i].score;}
else if (strcmp(stu[i].major,"网络")==0) //改后
{num1[1]++;
grades[1]=grades[1]+stu[i].score;}
else if (strcmp(stu[i].major,"物联网")==0) //改后
{num1[2]++;
grades[2]=grades[2]+stu[i].score;}
ave[i]=grades[i]/num1[i];}
printf("通信专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[0],grades[0],ave[0]);
printf("网络专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[1],grades[1],ave[1]);
printf("物联网专业情况如下:\n");
printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[2],grades[2],ave[2]);
printf("\n学生成绩输出如下:\n");
for(i=0;i<5;i++)
printf("姓名:%5s\t专业:%5s\t英语成绩:%d\t数学成绩:%d\tC语言成绩:%d\t总成绩:%d\n",stu[i].name,stu[i].major,stu[i].English,stu[i].Maths,stu[i].C,stu[i].score)

追问

这种我试过，什么结果都显示不出来- -

Answer 2

优化后的代码
#include<stdio.h>
#include <string.h>
struct Student
{
	char name[20];
	char major[20];
	int English;
	int Maths;
	int C;
	int score;
}stu[5]={
	{"zhang","通信",98,88,79,0},
	{"li","网络",67,78,89,0},
	{"lin","物联网",93,68,85,0},
	{"sun","网络",98,93,95,0},
	{"min","通信",88,79,69,0} };
void count (struct Student stu[5])
{
	int ave[3]={0};//初始化为0
	int num1[3]={0};//
	int grades[3]={0};//
    int i;
	for(i=0;i<5;i++)
	{
		stu[i].score=stu[i].English+stu[i].Maths+stu[i].C;
		if( !strcmp(stu[i].major,"通信" ) )//字符串比较
		{
			num1[0]++;
			grades[0]=grades[0]+stu[i].score;
		}
		else if	(!strcmp(stu[i].major,"网络"))//
		{
			num1[1]++;
			grades[1]=grades[1]+stu[i].score;
		}
		else if (!strcmp(stu[i].major,"物联网"))//
		{
			num1[2]++;
			grades[2]=grades[2]+stu[i].score;
		}
		else
		{
			printf("------------\n");
		}
		//ave[i]=grades[i]/num1[i];
	}

	for( i=0;i<3;i++ ) //单独计算平均值
		ave[i]=grades[i]/num1[i];

	printf("通信专业情况如下:\n");
	printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[0],grades[0],ave[0]);
	printf("网络专业情况如下:\n");
	printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[1],grades[1],ave[1]);
    printf("物联网专业情况如下:\n");
	printf("专业人数：%d\t专业总成绩:%d\t专业平均分:%d\n",num1[2],grades[2],ave[2]);
    printf("\n学生成绩输出如下:\n");
	for(i=0;i<5;i++)
		printf("姓名:%5s\t专业:%5s\t英语成绩:%d\t数学成绩:%d\tC语言成绩:%d\t总成绩:%d\n",
		stu[i].name,stu[i].major,stu[i].English,stu[i].Maths,stu[i].C,stu[i].score);
}

void main()
{
	count(stu);
}

Answer 3

struct Student count (struct Student stu[5])
{
	int ave[2];
	int num1[3];
	int grades[3];
	
	为什么第一个数组是ave[2]，后面的是[3]？？？？

应该是地址越界了