Question

帮忙看看这个c++程序错在哪了？怎么改？

题目：一个整数，它加上100后是一个完全平方数，再加上168又是一个完全平方数，请问该数是多少？
#include <iostream>
#include <math.h>
using namespace std;

int main()
{
int intNum;
int x,y;
for (intNum = 1; intNum <= 1000; intNum++)
{
x = int(sqrt(intNum + 100));
y = int(sqrt(intNum + 168));
if (x^2 == intNum + 100 && y^2 == intNum + 168);
{
printf("%d\n", intNum);
}
}
system("pause");
}

Answer 1

我帮你改好了，结果为156，对不对？：
#include <iostream>
#include <math.h>
using namespace std;

void main()
{
int intNum;
int x,y;
for (intNum = 1; intNum <= 1000; intNum++)
{
x = (sqrt(intNum + 100));
y = (sqrt(intNum + 168));
if (pow(x,2) == double(intNum + 100) && pow(y,2) == double(intNum + 168))
{
printf("%d\n", intNum);
}
}
system("pause");
}

Answer 2

#include <iostream>
#include <cmath>//这里使用cmath
using namespace std;

void main()
{
int intNum;
int x,y;
for (intNum = 1; intNum <= 1000; intNum++)
{
x = (sqrt(intNum + 100));
y = (sqrt(intNum + 168));
if (pow(x,2) == double(intNum + 100) && pow(y,2) == double(intNum + 168))
{
cout<<intNum<<endl;
}
}
system("pause");
return 0;//int main要有return
}

Answer 3

if ((x^2 == (intNum + 100) )&& (y^2 == (intNum + 168)));