Question

函数f（x）＝ax＋b（a不等于0）有一个零点是2，则函数g（x）＝bx平方－ax的零点是

Answer 1

f(x)=ax+b(a≠0)有一源好个零点是2 =>2a+b=0 b=-2a
g(x)=bx^2 -ax=-2ax^2-ax=0
=>x=0,-1/2，谢谢采纳雹庆铅差掘

Answer 2

f(x)=ax+b(a≠0)有一个大启零点是滚顷如乎唯2 =>2a+b=0 b=-2a
g(x)=bx^2 -ax=-2ax^2-ax=0
=>x=0,-1/2