已知f(sin x/2)=cosx+1,则f(cos x/2)=?
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f(sinx/2)=cosx+1
=1-2(sin(x/2))^2 +1
=2- 2(sin(x/2))^2
f(x)=2-2x^2
f(cos(x/2)^2=2-2(cos(x/2))^2
=2-(1+cosx)
=1-cosx
=1-2(sin(x/2))^2 +1
=2- 2(sin(x/2))^2
f(x)=2-2x^2
f(cos(x/2)^2=2-2(cos(x/2))^2
=2-(1+cosx)
=1-cosx
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