请问下这一题怎么做?必采纳的谢谢
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2sin20°+cos10°+tan20°sin10°
=2sin20°+cos10°+sin20°sin10°/cos20°
=(2sin20°cos20°+cos10°cos20°+sin20°sin10°)/cos20°
=[sin40°+cos(10°-20°)]/cos20°
=[sin40°+cos(-10°)]/cos20°
=(sin40°+cos10°)/cos20°
=(cos50°+cos10°)/cos20°
=2cos30°•cos20°/cos20°
=2cos30°
=√3
=2sin20°+cos10°+sin20°sin10°/cos20°
=(2sin20°cos20°+cos10°cos20°+sin20°sin10°)/cos20°
=[sin40°+cos(10°-20°)]/cos20°
=[sin40°+cos(-10°)]/cos20°
=(sin40°+cos10°)/cos20°
=(cos50°+cos10°)/cos20°
=2cos30°•cos20°/cos20°
=2cos30°
=√3
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