Question

化简 sin(θ-5π)/cos(3π-θ)*cos(π/2-θ)/sin(θ-3π)*cos(8π-θ)/sin(-θ-4π)+sin(-θ)

急啊

Answer 1

sin(θ-5π)/cos(3π-θ)*cos(π/2-θ)/sin(θ-3π)*cos(8π-θ)/sin(-θ-4π)+sin(-θ)
=(-sinθ/-cosθ)*(sinθ/-sinθ)*(cosθ/-sinθ)-sinθ
=tanθcotθ-sinθ
=1-sinθ

Answer 2

sin(θ-5π)/cos(3π-θ)*cos(π/2-θ)/sin(θ-3π)*cos(8π-θ)/sin(-θ-4π)+sin(-θ)
=-sina/-cosa ×sina/(-sina) × cosa/(-sina)-sina
=-1-sina