Question

数学简便运算题目

(3.7+5又2/3-1又2/3)÷0.11×0.03

7.2×7/6+5/6×7.2-7.2×2

2500÷2003/2004

25又1/3-[（22-19.75）-（17.25-16又1/3）]

简便运算，要有解题过程

Answer 1

(3.7+5又2/3-1又2/3)÷0.11×0.03
=(3.7+4)÷0.11×0.03
=7.7÷0.11×0.03
=70×0.03
=2.1

7.2×7/6+5/6×7.2-7.2×2
=7.2×(7/6+5/6-2)
=7.2×0
=0
2500÷2003/2004
=2500×2004/2003
=2500×(1+1/2003)
=2500+2500/2003
=2501又497/2003

25又1/3-[（22-19.75）-（17.25-16又1/3）]
=25又1/3-[22-19.75-（17.25-16又1/3]
=25又1/3-22+19.75+17.25-16又1/3
=9-22+37
=24

Answer 2

(3.7+5又2/3-1又2/3)÷0.11×0.03=（3.7+4）/0.11*0.03=7.7/0.11*0.03=2.1
7.2×7/6+5/6×7.2-7.2×2=7.2*(7/6+5/6-2)=0
25又1/3-[（22-19.75）-（17.25-16又1/3）]=25又1/3-[（22+16又1/3)-(19.75+17.25)]=25又1/3-(22+16又1/3-37)=(25又1/3-16又1/3)+15=24