
高数求极限 求详解!!!
2个回答
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x->0
sinx = x -(1/6)x^3 +o(x^3)
cosx = 1-(1/2)x^2 +o(x^2)
xcosx = x-(1/2)x^3 +o(x^3)
sinx -xcosx =(1/3)x^3 +o(x^3)
lim(x->0) (sinx- xcosx)/(sinx)^3
=lim(x->0) (sinx- xcosx)/x^3
=lim(x->0) (1/3)x^3/x^3
=1/3
sinx = x -(1/6)x^3 +o(x^3)
cosx = 1-(1/2)x^2 +o(x^2)
xcosx = x-(1/2)x^3 +o(x^3)
sinx -xcosx =(1/3)x^3 +o(x^3)
lim(x->0) (sinx- xcosx)/(sinx)^3
=lim(x->0) (sinx- xcosx)/x^3
=lim(x->0) (1/3)x^3/x^3
=1/3
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