Question

请问为什么r = random.nextInt(35)+1;还能得到0的值?

int arr[] = new int[5];boolean on_off = false;Random random = new Random();int r;public void randomNumber() { for (int i = 0; i < arr.length; i++) { r = random.nextInt(35)+1; for (int j = 0; j < arr.length; j++) { if (r == arr[j]) { on_off = false; break; } else { on_off = true; } } if (on_off == true) { arr[i] = r; } } System.out.print(Arrays.toString(arr) + "\t"); }请问为什么我还能得到0的值呢?懵逼!!!求大神指点..

Answer 1

Random r = new Random(); r.nextInt(101); random的nextInt(int n)方法可以生成一个介于0(包含)到n(不包含)之间的整数 nextInt(101)生成的就是0~100之间的随机数，包含0和100