Question

C++获取系统时间按照年-月-日格式化输出的运行错误，

代码如下：
time_t nowtime;
nowtime=time(NULL);
struct tm *local;
local=NULL;
local=localtime(&nowtime);
char *buffer=new char[12];
strftime(buffer,12,"%F",local);
cout<<buffer<<endl;

运行后报错，求解！

Answer 1

下面的程序在VC6上验证ok，你试试：

#include<iostream>
#include<ctime>
using namespace std;

int main()
{
time_t nowtime;
nowtime=time(NULL);
struct tm *local;
local=NULL;
local=localtime(&nowtime);
char *buffer=new char[12];
strftime(buffer,128,"%c",local);
cout<<buffer<<endl;

return 0;
}