1、数学计算题，要过程，一定会采纳~
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原式=（x-6y)/[(x+2y)(x-2y)]+2y/[x(x-2y]
=[x(x-6y)/[x(x+2y)(x-2y)]+[2y(x+2y)]/[x(x+2y)(x-2y)]
=[x²-6xy+2xy+4y²]/[x(x+2y)(x-2y)]
=(x²-4xy+4y²)/[x(x+2y)(x-2y)]
=(x-2y)²/[x(x+2y)(x-2y)]
=(x-2y)/[x(x+2y)]
=[x(x-6y)/[x(x+2y)(x-2y)]+[2y(x+2y)]/[x(x+2y)(x-2y)]
=[x²-6xy+2xy+4y²]/[x(x+2y)(x-2y)]
=(x²-4xy+4y²)/[x(x+2y)(x-2y)]
=(x-2y)²/[x(x+2y)(x-2y)]
=(x-2y)/[x(x+2y)]
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