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关于x,y多项式6mx²+4nxy+2x+2xy-x²+y+4不含二次项
2个回答
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合并同类项:(6m-1)x^2+(4n+2)xy+2x+y+4
其中的二次项是:(6m-1)x^2和(4n+2)xy,
要不含二次项,则6m-1=0,4n+2=0,得:6m=1,2n=-1,
所以:6m-2n+2=1-(-1)+2=4
希望能帮到你,
其中的二次项是:(6m-1)x^2和(4n+2)xy,
要不含二次项,则6m-1=0,4n+2=0,得:6m=1,2n=-1,
所以:6m-2n+2=1-(-1)+2=4
希望能帮到你,
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6mx²+4nxy+2x+2xy-x²+y+4
=6mx²-x²+4nxy+2xy+2x+y+4
=(6m-1)x²+(4n+2)xy+2x+y+4
多项式6mx²+4nxy+2x+2xy-x²+y+4不含二次项
即6m-1=0,4n+2=0
m=1/6
n=-1/2
2m²n+10m-4n+2-2m²n-4m+2n
=2m²n-2m²n+10m-4m-4n+2n+2
=6m-2n+2
=6*1/6-2*(-1/2)+2
=1+1+2
=4
=6mx²-x²+4nxy+2xy+2x+y+4
=(6m-1)x²+(4n+2)xy+2x+y+4
多项式6mx²+4nxy+2x+2xy-x²+y+4不含二次项
即6m-1=0,4n+2=0
m=1/6
n=-1/2
2m²n+10m-4n+2-2m²n-4m+2n
=2m²n-2m²n+10m-4m-4n+2n+2
=6m-2n+2
=6*1/6-2*(-1/2)+2
=1+1+2
=4
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