Question

求一C++语言源程序用if-else、switch、for三种语句写C++程序输入某年某月某日判断这一天是这一年的第几天

求一C++语言源程序，利用if-else、switch、for三种语句写一C++程序解决问题：输入某年某月某日，判断这一天是这一年的第几天?(要求输入的年份智能在1-12月之间、输入的号数只能在是在1到当月最大天数范围之内、

Answer 1

写好了，有点笨不要笑。。 #include <iostream> using namespace std; int main() { int year,month,day,no; cout<<"Year:"; cin>>year; cout<<"Month:"; cin>>month; cout<<"Day:"; cin>>day; if(year%400==0||year%4==0&&year%100!=0) //是闰年的情况 switch(month) { case 1: no=day; break; case 2: no=31+day; break; case 3: no=1+31+28+day; break; case 4: no=1+31+28+31+day; break; case 5: no=1+31+28+31+30+day; break; case 6: no=1+31+28+31+30+31+day; break; case 7: no=1+31+28+31+30+31+30+day; break; case 8: no=1+31+28+31+30+31+30+31+day; break; case 9: no=1+31+28+31+30+31+30+31+31+day; break; case 10: no=1+31+28+31+30+31+30+31+31+30+day; break; case 11: no=1+31+28+31+30+31+30+31+31+30+31+day; break; case 12: no=1+31+28+31+30+31+30+31+31+30+31+30+day; break; default: cout<<"你的输入有误！"<<endl; return 0; } else //不是闰年的情况 switch(month) { case 1: no=day; break; case 2: no=31+day; break; case 3: no=31+28+day; break; case 4: no=31+28+31+day; break; case 5: no=31+28+31+30+day; break; case 6: no=31+28+31+30+31+day; break; case 7: no=31+28+31+30+31+30+day; break; case 8: no=31+28+31+30+31+30+31+day; break; case 9: no=31+28+31+30+31+30+31+31+day; break; case 10: no=31+28+31+30+31+30+31+31+30+day; break; case 11: no=31+28+31+30+31+30+31+31+30+31+day; break; case 12: no=31+28+31+30+31+30+31+31+30+31+30+day; break; default: cout<<"你的输入有误！"<<endl; return 0; } cout<<"你输入的日期是这一年的第"<<no<<"天"<<endl; system("pause"); return 0; }