试用简便方法、1/2[x-1/2(x-1)+1]=2/3(x-1)
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2012-01-18 · 知道合伙人教育行家
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1/2[x-1/2(x-1)+1]=2/3(x-1)
1/2[(x-1)+1-1/2(x-1)+1]=2/3(x-1)
1/2[(x-1)-1/2(x-1)+2]=2/3(x-1)
1/2[1/2(x-1)+2]=2/3(x-1)
1/4(x-1)+1=2/3(x-1)
(2/3-1/4)(x-1)=1
5/12(x-1)=1
x-1=12/5
x=1+12/5=17/5
1/2[(x-1)+1-1/2(x-1)+1]=2/3(x-1)
1/2[(x-1)-1/2(x-1)+2]=2/3(x-1)
1/2[1/2(x-1)+2]=2/3(x-1)
1/4(x-1)+1=2/3(x-1)
(2/3-1/4)(x-1)=1
5/12(x-1)=1
x-1=12/5
x=1+12/5=17/5
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