Question

详细解题过程？

详细解一下这个三元一次方程

Answer 1

4(2x+4y+y++z) =1880 (1)

3z =2x (2)
4y =x (3)
from (3)
4y=x
y=x/4 =3k
y=3k, x=12k
from (2)
3z=2x
=24k
z=8k
from (1)
4(2x+4y+y++z) =1880
4(2x+5y+z) =1880
4(24k+15k+8k)=1880
k=10
x=12k =120
y=3k=30
z=8k = 80

Answer 2

由第二个方程可知道z=2/3x,y=1/4x,然后带入第一个得（2x+x+2/3x+1/4x）×4=188，所以x=12,故y=3,z=8