Question

(m+2n)²+4(mn+2n²)+4n²因式分解？

Answer 1

(m+2n)²+4(mn+2n²)+4n²因式分解计算
(m+2n)²+4(mn+2n²)+4n²
=(m+2n)²+4(m+2n)n+4n²
=[(m+2n)+2n]²
=(m+4n)²

Answer 2

解：（m＋2n）^2+4（mn＋2n^2）+4n^2
＝（m+2n）^2+2×（m＋2n）×（2n）＋（2n）^2
＝[(m＋2n）＋2n]^2
＝（m＋4n）^2

Answer 3

(m + 2n)² + 4(mn + 2n²) + 4n²
= (m + 2n)² + 2(2n)(m + 2n) + (2n)²
= (m + 4n)²

Answer 4

(m+2n)²+4(mn+2n²)+4n²
=(m+2n)²+2×(m+2n)×2n+(2n)²
=[(m+2n)+2n]²
=(m+4n)²