Question

java中两个数相除，得到的百分数怎么求？？

public class a {
public static void main(String[] args) {
int leng = 5900;
int width = 2350;
int height = 2393;
int l = 120;
int w = 130;
int h = 333;
int ll = leng/l;//49
int ww = width/w;//15
int hh = height/h;//7
int sum = (ll)*(ww)*(hh);//5145
int lwh = l*w*h;
int per = (lwh*sum)*100/(leng*width*height);
System.out.println(per + "%");
}
}

为什么我求出来的是0啊？？大侠们，帮帮忙啊！！！！

Answer 1

数据的值，远超于int long double的表示范围了。
要用BigInteger 和BigDecimal这些大数据类型。
+——add();

System.out.println(BigInteger.valueOf(10).add(BigInteger.valueOf(5)));

- ——subtract();

System.out.println(BigInteger.valueOf(10).subtract(BigInteger.valueOf(5)));

*——multiply();

System.out.println(BigInteger.valueOf(10).multiply(BigInteger.valueOf(5)));

/——divide();
System.out.println(BigInteger.valueOf(10).divide(BigInteger.valueOf(5)));

Answer 2

哥们，超int范围了，给你改好了，你只要改变一下操作的顺序就可以了
public class exercise1 {
public static void main(String[] args) {
int leng = 5900;
int width = 2350;
int height = 2393;
int l = 120;
int w = 130;
int h = 333;
int ll = leng/l;//49
int ww = width/w;//18
int hh = height/h;//7
int sum = (ll)*(ww)*(hh);//5145
int lwh = l*w*h;
double a=lwh/leng;
double b=sum/width;
double per = a*b*100/height;
System.out.println(per + "%");
}
}

Answer 3

你这个数值超范围了自己拿计算器算算也知道 int per不能定义浮点数
记得类名首字母大写哦 亲

Answer 4

int 类型 没 有小数用double类型