Question

如何在java中发送post请求

Answer 1

将表单发送的地址修改为你编写的Servlet.java的虚拟路径如下图：

Answer 2

package com.test;

import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.util.EntityUtils;

public class D {
public static void main(String[] args){
List<NameValuePair> nvps= new ArrayList<NameValuePair>();
nvps.add(new BasicNameValuePair("id", "1"));
String url="https://www.hao123.com/";

HttpClient httpClient = null;
String response="";
try {

HttpPost post = new HttpPost(url);
post.setHeader("Connection", "close");

httpClient = new DefaultHttpClient();
post.setEntity(new UrlEncodedFormEntity(nvps));
HttpResponse httpres= httpClient.execute(post);

if (httpres.getStatusLine().getStatusCode() >= 300) {
System.out.println("Request Failed,Code:" + httpres.getStatusLine().getStatusCode() + ",URL:" + url);
}

response = EntityUtils.toString(httpres.getEntity(), "utf-8");
}catch(Exception e){

e.printStackTrace();
}finally{
if(httpClient!=null){
httpClient.getConnectionManager().shutdown();
}

}
System.out.println(response);

}
}

需要httpclient-4.1.3.jar，httpcore-4.1.4.jar和commons-logging-1.1.1.jar