Question

几道初二的分解因式

分解下列因式(要过程)(1).(y-x)^2+2x-2y(2).a^2-16(a-b)^2

Answer 1

1).(y-x)²+2x-2y=(x-y)²+2(x-y)=(X-y)(x-y+2)
2).a²-16(a-b)²=[a+4(a-b)][a-4(a-b)]=(5a-4b)(-3a+4b)

Answer 2

解,1）。（y-x）²+2x-2y=（x-y)²+2（x-y)=(x-y)(x-y+2); 2),a²-16（a-b)²=（a+4a-4b)(a-4a+4b）=（5a-4b)(4b-3a)..