Question

有10%的氢氧化钠溶液16克,用20%的盐酸恰好中和.求所得溶液中溶质的质量分数?

求解题过程，要详细

Answer 1

NaOH+HCl===NaCl+H2O
40.......36.5.....58.5
1.6.......x...........y
x=1.6*36.5/40=1.46g；m(溶液)=1.46/20%=7.3g
y=1.6*58.5/40=2.34g；NaCl%=2.34/(16+7.3)=10%

Answer 2

设盐酸溶液质量xg
NaOH+ HCl = NaCl+H2O
40 36.5 58.5
1.6 20%X Y X=7.3 Y=2.34 最后溶质就是NaCl 质量分数=2.34/(16+7.3)=10%