Question

C++语言怎么才能限定只输入整数数字呢？

#include <iostream>
using namespace std;

int main()
{
int number;
cout << "Enter a number ";
cin >> number;
if ((number%5!=0)&&(number%6!=0))
cout << number <<" is not divisible by either 5 or 6. " << endl;
else if ((number%5==0)&&(number%6==0))
cout << number <<" is divisible by both 5 and 6. " <<endl;
else
cout << number <<" is divisible by 5 or 6, but not both. " <<endl;
return 0;
}

Answer 1

#include <iostream>
using namespace std;
int main()
{
int number,s;
char str[20];
cout<<"请输入一个整数噢亲~（淘宝小二语）~"<<endl;
cin>>number;
s=cin.rdstate();

while(s)
{ cin.clear();
cin>>str;
cout<<"抱歉噢亲，您的输入为非整数，请您重新输入╮(╯_╰)╭"<<endl;
cin>>number;
s=cin.rdstate();
}
cout<<"亲，您刚才成功地输入了一个整数噢："<<number<<" O(∩_∩)O~"<<endl;
cout<<endl;

if ((number%5!=0)&&(number%6!=0))
cout << number <<" is not divisible by either 5 or 6. " << endl;
else if ((number%5==0)&&(number%6==0))
cout << number <<" is divisible by both 5 and 6. " <<endl;
else
cout << number <<" is divisible by 5 or 6, but not both. " <<endl;
cout<<endl;

cout<<"恭喜您亲，您的程序成功运行了噢~~~~"<<endl;

cin.get();//防止程序输出一闪而过
cin.get();//防止程序输出一闪而过
return 0;

}

改好了，也调试好了，只能限定整数输入，可以反复多次错误输入非整数，要不要选我最佳答案，自己凭良心吧，网友们都看着的。......

追问

Run-Time Check Failure #2 - Stack around the variable 'number' was corrupted.
Run-Time Check Failure #2 - Stack around the variable 'str' was corrupted.
怎么我调试就出现这两个错误？？

追答

你重新建个工程试试，我这边重新编译通过了，或者加qq753743312，在线谈

Answer 2

整数数字就是char的取值范围是从'0'到'9',超出这个范围的取值自动被忽略，
自己写个函数，如下
char myInputInt()
{
char c;
BOOL bCon=TRUE;
while(bCon)
{
scanf("%d",&c);
if(c>='0' && c<='9')
{
bCon=FALSE;
return c;

}

}

}

Answer 3

想要保证用户只能输入数字的话得自己写函数处理:
#include <io.h>
int getNumber()
{
int ret = 0;
char buf[32] = {0};
char c;
int i=0;
while((c=getch())!='\n')
{
if(i>=10&&c!='\b') continue;//输满10个数后只能接受回车或退格backspace
if(c>='0'&&c<='9') {putchar(c);buf[i++]=c;}//数字保存并回显
else if(c=='\b'&&i>0) {printf("\b \b"); buf[--i]='\0';}
}
sscanf(buf,"%d",&ret);
return ret;
}

Answer 4

你先用一个字符串来存，搜索看有没有不是数字的（比如英文啊，小数点啊，开头是0啊），有的话清空，提示重新输入。然后用sscanf（）函数再读入到int里面...