Question

函数y=1/2sin(x-π/3)的对称轴

Answer 1

选c
函数图像向左平移加，向右平移减
你这明显是向左平移π/3个单位
正常对称轴=kπ+π/2
此时=kπ+π/2-π/3
当k=0时
x=π/6
故选c

Answer 2

对称轴的梯度=0
所以dy/dx
=
0
y
=
(1/2)
sin
(x
-
π/3)
dy/dx
=
(1/2)
cos
(x
-
π/3)
当
dy/dx
=
0
0
=
(1/2)
cos
(x
-
π/3)
cos
(x
-
π/3)
=
0
x
-
π/3
=
π/2
x
=
5π/6
对称轴，x
=
5π/6
纯手打，蒙采纳，谢谢~~