已知a^(2/3)+b^(2/3)=4,x=a+3a^(1/3)b^(2/3),y=b+3a^(2/3)b^(1/3)
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x=a+3a^(1/3)b^(2/3),y=b+3a^(2/3)b^(1/3)，
x+y=[a^(1/3)+b^(1/3)]^3,
x-y=[a^(1/3)-b^(1/3)]^3,
(x+y)^(2/3)+(x-y)^(2/3)
=[a^(1/3)+b^(1/3)]^2+[a^(1/3)-b^(1/3)]^2
=2[a^(2/3)+b^(2/3)]
=8.
x+y=[a^(1/3)+b^(1/3)]^3,
x-y=[a^(1/3)-b^(1/3)]^3,
(x+y)^(2/3)+(x-y)^(2/3)
=[a^(1/3)+b^(1/3)]^2+[a^(1/3)-b^(1/3)]^2
=2[a^(2/3)+b^(2/3)]
=8.
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