Question

解二元一次数学题-3X平方+6X大于2 我需要详细过程 如何因式分解的 谢谢

Answer 1

-3X²+6X＞2 同时乘以-3得
9x²-18x＜-6 同是除以3得到
3X²-6X＜-2
3（X²-2x）＜-2
3(X²-2x+1-1)＜-2
3(x-1)²-3＜-2
3(x-1)²＜1
(x-1)²＜1/3
-√3/3＜x-1＜√3/3
1-√3/3＜x＜1+√3/3

Answer 2

-3X²+6X＞2
3x²-6x＜-2
3(x²-2x)＜-2
3(x-1)²-3＜-2
3(x-1)²＜1
(x-1)²＜1/3
-√3/3＜x-1＜√3/3
1-√3/3＜x＜1+√3/3

Answer 3

-3x^2+6x＞2
-3x^2+6x-2＞0
3x^2-6x+2＜0
3(x^2-2x+1)-1＜0
3(x-1)^2-1＜0
(x-1)^2＜1/3
-1/√3＜x-1＜1/√3
1-1/√3＜x＜1+√3

Answer 4

-3x^2+6x>2
(-3x^2+6x)/3>2/3
-x^2+2x>2/3
x^2-2x>-2/3
x^2-2x+1>-2/3+1
(x-1)^2>1/3
x-1>正负3分之根号3
x>1加3分之根号3 或1减3分之根号3