(log3(2)+log9(2))*(log4(3)+log8(3))
2个回答
展开全部
(log3(2) + log9(2)) * (log4(3) + log8(3))
= (lg2/lg3 + lg2/lg9) * (lg3/lg4 + lg3/lg8))
= [lg2/lg3 + lg2/(2lg3)] * [lg3/(2lg2) + lg3/(3lg2)]
= [(2lg2+lg2)/(2lg3)] * [(3lg3+2lg3)/(6lg2)]
= 3lg2/(2lg3)] * 5lg3/(6lg2)
= 3/2 * 5/6
= 5/4
= (lg2/lg3 + lg2/lg9) * (lg3/lg4 + lg3/lg8))
= [lg2/lg3 + lg2/(2lg3)] * [lg3/(2lg2) + lg3/(3lg2)]
= [(2lg2+lg2)/(2lg3)] * [(3lg3+2lg3)/(6lg2)]
= 3lg2/(2lg3)] * 5lg3/(6lg2)
= 3/2 * 5/6
= 5/4
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
