Question

初二数学分式约分题

x^2+xy/(x+y). x^2-y^2/(x-y)^2

Answer 1

x^2+xy/(x+y).
＝x(x+y)/(x+y)
=x

x^2-y^2/(x-y)^2
=(x+y)(x-y)/(x-y)²
=(x+y)/(x-y)

Answer 2

我觉得原题应该是这样的吧：
（x^2+xy）/(x+y). （ x^2-y^2）/(x-y)^2
缺了两个括号。以下是改正后的运算步骤：
（x^2+xy）/(x+y). =x(x+y)/(x+y)=x
（ x^2-y^2）/(x-y)^2=(x+y)(x-y)/(x-y)^2=(x+y)/(x-y)

Answer 3

1、原式=x(x+y)/(x+y)=x
2、原式=（x+y)(x-y)/(x-y)²=(x+y)/(x-y)

Answer 4

(1)(a^3-4ab^2)/(a^3-4a^2b+4ab^2) =a(a^2-4b^2)/a(a^2-4ab+4b^2) =[a(a-2b)(a+2b)]/a(a-2b)^2 =(a+2b)/(a-2b) =