Question

8x-2(1-x)=9x-3(x+2) 3/2[2/3*(4/3x-1/3)]=4/5x 3(2y+1)/4+1=4(2y+1)/3 1/5[(1/2y-1)-6]=1

x-0.2/0.3+0.5x-1/0.5=1

解方程

Answer 1

8x-2(1-x)=9x-3(x+2)
8x-21+2x=9x-3x-6
8x+2x-9x+3x=-6+21
4x=15
x=15/4

3/2[2/3*(4/3x-1/3)]=4/5x
4/3x-1/3=4/5x
20x-5=12x
8x=5
x=5/8

3(2y+1)/4+1=4(2y+1)/3
4(2y+1)+12=3(2y+1)
8y+4+12=6y+3
8y-6y=3-4-12
2y=-13
y=-13/2

1/5[(1/2y-1)-6]=1
1/2y-1-6=5
y-2-12=10
y=10+12+2=24

x-0.2/0.3+0.5x-1/0.5=1
x-2/3+x/2-2=1
6x-4+3x-12=6
6x+3x=6+4+12
9x=22
x=22/9

最后一题如果是：
(x-0.2)/0.3+(0.5x-1)/0.5=1
10x/3-2/3+x-2=1
10x-2+3x-6=3
10x+3x=3+2+6
13x=11
x=11/13

Answer 2

x=11/13

Answer 3

8x-2(1-x)=9x-3(x+2) 3/2[2/3*(4/3x-1/3)]=4/5x 3(2y+1)/4+1=4(2y+1)/3 1/5[(1/2y-1)-6]=1