Question

①x-1分之x-(x-1)(x+2)分之三-1 要过程

①x-1分之x-(x-1)(x+2)分之三-1 要过程
②a-1分之2a+2/（a+1）-a平方-2a+1分之a平方-1 要过程
③x+y分之1-x-y分之1+x平方-y平方分之2x 要过程
快！！！做完还有追加

Answer 1

①x-1分之x-(x-1)(x+2)分之三-1
=(x-1)(x+2)分之x(x+2) - (x-1)(x+2)分之3-1
=[(x-1)(x+2)]分之[x(x+2) -3-(x-1)(x+2)]
=[(x-1)(x+2)]分之[x²+2x -3- x²- x+2)]
=[(x-1)(x+2)]分之(x-1)
=x+2分之1

②a-1分之2a+2/（a+1）-a平方-2a+1分之a平方-1
=2a/(a-1)+2/（a+1）-(a-1)²分之(a+1)(a-1 )
= 2a/(a-1)+2/（a+1）-(a+1)/(a-1)
=1+2/(a+1)

③x+y分之1-x-y分之1+x平方-y平方分之2x
=1/(x+y)-1/(x-y)+2x/[(x+y)(x-y)]
=[(x-y)-(x+y)+2x] / [(x+y)(x-y)]
=(2x-2y) /[(x+y)(x-y)]
=2/((x+y)

Answer 2

时代复分