Question

(1/a+1/b)的平方 / (a的平方分之一-b的平方分之一）要过程

Answer 1

[(1/a)+(1/b)]²/[(1/a²)-(1/b²)]
=[(a+b)²/a²b²]/[(b²-a²)/a²b²]
=(a+b)²/(b²-a²)
=(a+b)/(b-a)