Question

简便算法~~~

212121分之121121乘以212212分之121212=?
简便方法给我!!有追加分 重谢

Answer 1

121121*121212/212121*212212,先别用分子与分母除以4(121212,212212),1001(121121,212212),3(121212,212121),10101(121212,212121),最后结果121/371

Answer 2

212121分之121121=121121÷212121

212212分之121212=121212÷212212

212121分之121121乘以212212分之121212
=121121÷212121×121212÷212212
=121212÷212121×121121÷212212
=(121212÷30303)÷(121212÷30303)×121121÷212212
=(4÷7)×121121÷212212
=(4÷7)×(121121÷7)÷(212212÷7)
=(4÷7)×(17303÷30316)
=(4/7)×(17303/30316)
=(1/7)×(17303/30316÷4)
=(1/7)×(17303/7579)
=17303/7579×7
=17303/53053

Answer 3

规律是上面两个数的分子和分母都是3的倍数.所以不断分子分母同时除3,运算比较简单

Answer 4

212121分之121121乘以212212分之121212
=121121÷212121×121212÷212212
=121212÷212121×121121÷212212
=(121212÷30303)÷(121212÷30303)×121121÷212212
=(4÷7)×121121÷212212
=(4÷7)×(121121÷7)÷(212212÷7)
=(4÷7)×(17303÷30316)
=(4/7)×(17303/30316)
=(1/7)×(17303/30316÷4)
=(1/7)×(17303/7579)
=17303/7579×7
=17303/53053
最好问老师

Answer 5

78*(200-1)=78*200-78*1
(25*4)*2*(4*25)*5
4.6*(100+1)
4.17-(0.25+0.75)