初二数学计算题
3x^（2n）-12/x^（2n+3）-6x^（n+3）+9x^3*x^（n）+3/x^（n）-2÷3x^（n）+6/x^（n+1）+3x大家写在纸上看比较清晰写出来加悬...
3x^（2n）-12/ x^（2n+3）-6x^（n+3）+9x^3 * x^（n）+3/x^（n）-2÷3x^（n）+6/x^（n+1）+3x
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大家写在纸上看比较清晰 写出来加悬赏 展开
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[3x^(2n)-12] / { x^(2n+3) - 6x^(n+3)+9x^3} * (x^n+3) /(x^n-2) ÷ [3x^n+6] / [x^(n+1)+3x]
= 3(x^n+2)(x^n-2) / {x^3[x^(2n) - 6x^n+9]} * (x^n+3) / (x^n-2) ÷ [3(x^n+2)] / [x(x^n+3)]
= 3(x^n+2)(x^n-2) / [x^3(x^n-3)^2] * (x^n+3) / (x^n-2) * [x(x^n+3)] / [3(x^n+2)]
= 1 / [x^2(x^n-3)^2] * (x^n+3) * (x^n+3)
= (x^n+3)^2/[x^2(x^n-3)^2
[3x^(2n)-12] / { x^(2n+3) + 6x^(n+3)+9x^3} * (x^n+3) /(x^n-2) ÷ [3x^n+6] / [x^(n+1)+3x]
= 3(x^n+2)(x^n-2) / {x^3[x^(2n) +6x^n+9]} * (x^n+3) / (x^n-2) ÷ [3(x^n+2)] / [x(x^n+3)]
= 3(x^n+2)(x^n-2) / [x^3(x^n+3)^2] * (x^n+3) / (x^n-2) * [x(x^n+3)] / [3(x^n+2)]
= 1 / [x^2(x^n+3)^2] * (x^n+3) * (x^n+3)
= 1/x^2
= 3(x^n+2)(x^n-2) / {x^3[x^(2n) - 6x^n+9]} * (x^n+3) / (x^n-2) ÷ [3(x^n+2)] / [x(x^n+3)]
= 3(x^n+2)(x^n-2) / [x^3(x^n-3)^2] * (x^n+3) / (x^n-2) * [x(x^n+3)] / [3(x^n+2)]
= 1 / [x^2(x^n-3)^2] * (x^n+3) * (x^n+3)
= (x^n+3)^2/[x^2(x^n-3)^2
[3x^(2n)-12] / { x^(2n+3) + 6x^(n+3)+9x^3} * (x^n+3) /(x^n-2) ÷ [3x^n+6] / [x^(n+1)+3x]
= 3(x^n+2)(x^n-2) / {x^3[x^(2n) +6x^n+9]} * (x^n+3) / (x^n-2) ÷ [3(x^n+2)] / [x(x^n+3)]
= 3(x^n+2)(x^n-2) / [x^3(x^n+3)^2] * (x^n+3) / (x^n-2) * [x(x^n+3)] / [3(x^n+2)]
= 1 / [x^2(x^n+3)^2] * (x^n+3) * (x^n+3)
= 1/x^2
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