
2道初二数学题,要详细过程!
1.已知y分之x=3,求x²-xy+y²分之x²+2xy-3y²(注意:要用两种方法。)2.通分:(1)3y分之x与2y²...
1.已知y分之x=3,求x²-xy+y²分之x²+2xy-3y²(注意:要用两种方法。)
2.通分:
(1)3y分之x与2y²分之3x
(2)a²b分之6c与3ab²分之c
(3)2x+2y分之x-y与(x+y)²分之xy
(4)4m²-9分之2mn与2m+3分之2m-3
要详细解答过程!!!!!!!!!!!!! 展开
2.通分:
(1)3y分之x与2y²分之3x
(2)a²b分之6c与3ab²分之c
(3)2x+2y分之x-y与(x+y)²分之xy
(4)4m²-9分之2mn与2m+3分之2m-3
要详细解答过程!!!!!!!!!!!!! 展开
3个回答
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1.已知y分之x=3,求x²-xy+y²分之x²+2xy-3y²(注意:要用两种方法。)
解:
X/Y=3
Y/X=1/3
(X²+2XY-3Y²)/(X²-XY+Y²)
=[(X²+2XY-3Y²)/X²]/[(X²-XY+Y²)/X²]
=(1+2XY/X²-3Y²/X²)/(1-XY/X²+Y²/X²)
=[1+2(Y/X)-3(Y/X)²]/[1-(Y/X)+(Y/X)²]
=[1+2×1/3-3×(1/3)²]/[1-1/3+(1/3)²] (把Y/X=1/3代入)
=(1+2/3-1/3)/(1-1/3+1/9)
=(4/3)/(7/9)
=12/7
(X²+2XY-3Y²)/(X²-XY+Y²)
=[(X²+2XY-3Y²)/Y²]/[(X²-XY+Y²)/Y²]
=(X²/Y²+2XY/Y²-3)/(X²/Y²-XY/Y²+1)
=[(X/Y)²+2(X/Y)-3]/[(X/Y)²-(X/Y)+1]
=(3²+2×3-3)/(3²-3+1) (把X/Y=3代入)
=(9+2×3-3)/(9-3+1)
=12/7
2.通分:
(1)3y分之x与2y²分之3x
X/3Y 3X/2Y²
(X/3Y)×(2Y/2Y)=2XY/6Y²
(3X/2Y²)×(3/3)=9X/6Y²
通分分母为6Y²
(2)a²b分之6c与3ab²分之c
6c/a²b c/3ab²
(6c/a²b)×(3b/3b)=18bc/3a²b²
(c/3ab²)×(a/a)=ac/3a²b²
通分分母为3a²b²
(3)2x+2y分之x-y与(x+y)²分之xy
(X-Y)/(2X+2Y)=(X-Y)/2(X+Y)
XY/(X+Y)²
[(X-Y)/2(X+Y)] ×[(X+Y)/(X+Y)]
=[(X-Y)×(X+Y)]/[2(X+Y)²]
=(X²-Y²)/2(X+Y)²
XY/(X+Y)²
=[XY/(X+Y)²]×(2/2)
=2XY/2(X+Y)²
通分分母2(X+Y)²
(4)4m²-9分之2mn与2m+3分之2m-3
2mn/(4m²-9)=2mn/(2m+3)(2m-3)
(2m-3)/(2m+3)
[(2m-3)/(2m+3)] ×[(2m-3)/(2m-3)]
=(2m-3)²/(2m+3)×(2m-3)
=(4m²-12m+9)/(4m²-9)
通分分母4m²-9
解:
X/Y=3
Y/X=1/3
(X²+2XY-3Y²)/(X²-XY+Y²)
=[(X²+2XY-3Y²)/X²]/[(X²-XY+Y²)/X²]
=(1+2XY/X²-3Y²/X²)/(1-XY/X²+Y²/X²)
=[1+2(Y/X)-3(Y/X)²]/[1-(Y/X)+(Y/X)²]
=[1+2×1/3-3×(1/3)²]/[1-1/3+(1/3)²] (把Y/X=1/3代入)
=(1+2/3-1/3)/(1-1/3+1/9)
=(4/3)/(7/9)
=12/7
(X²+2XY-3Y²)/(X²-XY+Y²)
=[(X²+2XY-3Y²)/Y²]/[(X²-XY+Y²)/Y²]
=(X²/Y²+2XY/Y²-3)/(X²/Y²-XY/Y²+1)
=[(X/Y)²+2(X/Y)-3]/[(X/Y)²-(X/Y)+1]
=(3²+2×3-3)/(3²-3+1) (把X/Y=3代入)
=(9+2×3-3)/(9-3+1)
=12/7
2.通分:
(1)3y分之x与2y²分之3x
X/3Y 3X/2Y²
(X/3Y)×(2Y/2Y)=2XY/6Y²
(3X/2Y²)×(3/3)=9X/6Y²
通分分母为6Y²
(2)a²b分之6c与3ab²分之c
6c/a²b c/3ab²
(6c/a²b)×(3b/3b)=18bc/3a²b²
(c/3ab²)×(a/a)=ac/3a²b²
通分分母为3a²b²
(3)2x+2y分之x-y与(x+y)²分之xy
(X-Y)/(2X+2Y)=(X-Y)/2(X+Y)
XY/(X+Y)²
[(X-Y)/2(X+Y)] ×[(X+Y)/(X+Y)]
=[(X-Y)×(X+Y)]/[2(X+Y)²]
=(X²-Y²)/2(X+Y)²
XY/(X+Y)²
=[XY/(X+Y)²]×(2/2)
=2XY/2(X+Y)²
通分分母2(X+Y)²
(4)4m²-9分之2mn与2m+3分之2m-3
2mn/(4m²-9)=2mn/(2m+3)(2m-3)
(2m-3)/(2m+3)
[(2m-3)/(2m+3)] ×[(2m-3)/(2m-3)]
=(2m-3)²/(2m+3)×(2m-3)
=(4m²-12m+9)/(4m²-9)
通分分母4m²-9
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解:1)(x²+2xy-3y²) /(x²-xy+y²)
分子分母同时除以x^2 (第二种方法为除以y^2)
原式=(1+2y/x-3(y/x)^2)/(1-y/x+(y/x)^2)
=(1+2/3-1/3)/(1-1/3+1/9)
=12/7
2)
x/3y 与3x/2y^2 通分后分母为 6y^2
a²b分之6c与3ab²分之c 通分后分母为 3a^2b^2
2x+2y分之x-y与(x+y)²分之xy 通分后分母为 2(x+y)²
4m²-9分之2mn与2m+3分之2m-3 通分后分母为 4m²-9
分子分母同时除以x^2 (第二种方法为除以y^2)
原式=(1+2y/x-3(y/x)^2)/(1-y/x+(y/x)^2)
=(1+2/3-1/3)/(1-1/3+1/9)
=12/7
2)
x/3y 与3x/2y^2 通分后分母为 6y^2
a²b分之6c与3ab²分之c 通分后分母为 3a^2b^2
2x+2y分之x-y与(x+y)²分之xy 通分后分母为 2(x+y)²
4m²-9分之2mn与2m+3分之2m-3 通分后分母为 4m²-9
更多追问追答
追问
第二题通分能详细一点吗???详细到最后的结果、!!!
追答
假设你写的“与”是加
1) x/3y +3x/2y^2
=x*2y/6y^2 +3x*3/6y^2
=(2xy+9x)/6y^2
2) 6c/a²b+c/3ab²
=6c*3b/3a^2b^2+c*a/3a^2b^2
=(18bc+ac)/3a^2b^2
后两问类似,这分式太难打了,你就自己算一下吧,不好意思了!
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哎,哥们会做可惜没办法帮你呀!分数太难打了......不好意思
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