Question

数学题（计算，八年级下学期）如下

（1）x-3分之x²-x-6÷x²-5x+6分之x-3

（过程）O(∩_∩)O谢谢，我会追加悬赏的（最好的

Answer 1

(x^2-x-6)/(x-3)÷[(x-3)/(x^2-5x+6)]
=(x^2-x-6)/(x-3)(x^2-5x+6)/(x-3)
=(x+2)(x-3)(x-2)(x-3)/(x-3)^2
=(x-2)(x+2)
=x^2-4
x^2就是x²

追问

抱歉，能把乘号体现出来吗？

追答

(x²-x-6)/(x-3)÷[(x-3)/(x²-5x+6)]
=(x²-x-6)/(x-3)×(x²-5x+6)/(x-3)
=(x+2)×(x-3)×(x-2)×(x-3)/(x-3)²
=(x-2)×(x+2)
=x²-4

Answer 2

x-3分之x²-x-6÷x²-5x+6分之x-3
=（x²-x-6）（x²-5x+6）/(x-3)(x-3)
=(x-3)(x+2)(x-2)(x-3)/(x-3)(x-3)
=(x+2)(x-2)

Answer 3

(x^2-x-6)/(x-3)÷[(x-3)/(x^2-5x+6)]
=(x+2)(x-3)/ (x-3) * (x-2)(x-3)/(x-3)
=(x-2)(x+2)
=x^2-4