[2XY^2/(X+Y)]^3/[XY^3/(X^2-Y^2)]^2*[1/2(X-Y)]^2 其中x=-1/2 y=2/3
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原式=[8x^3y^6/(x+y)^3] / [x^2y^6/(x^2-y^2)^2] * [1/4(x-y)^2]
=[8x^3y^6/(x+y)^3] * [(x-y)^2(x+y)^2/x^2y^6] * [1/4(x-y)^2]
=[8x(x-y)^2/(x+y)] * [1/4(x-y)^2]
=2x/x+y
=2 * (-1/2)/(-1/2+2/3)
= - 6
=[8x^3y^6/(x+y)^3] * [(x-y)^2(x+y)^2/x^2y^6] * [1/4(x-y)^2]
=[8x(x-y)^2/(x+y)] * [1/4(x-y)^2]
=2x/x+y
=2 * (-1/2)/(-1/2+2/3)
= - 6
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