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1.a+b+2b²/a-b
=[(a+b)(a-b)+2b²]/(a-b)
=(a²-b²+2b8)/(a-b)
=(a+b)(a-b)/(a-b)
=a+b
2.x²/x-1-x-1
=[x²-(x+1)(x-1)]/(x-1)
=(x²-x²+1)/(x-1)
=1/(x-1)
=[(a+b)(a-b)+2b²]/(a-b)
=(a²-b²+2b8)/(a-b)
=(a+b)(a-b)/(a-b)
=a+b
2.x²/x-1-x-1
=[x²-(x+1)(x-1)]/(x-1)
=(x²-x²+1)/(x-1)
=1/(x-1)
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第二个没看出来= =还能再说清楚点吗
追答
x²/x-1-x-1
=x²/(x-1)-(x+1)
=[x²-(x+1)(x-1)]/(x-1)
=(x²-x²+1)/(x-1)
=1/(x-1)
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