Question

帮我解下面这道数学题！

已知（x+y）(x+y-10)+25=0,且x-y=2，求x，y的值？

Answer 1

(x+y）(x+y-10)+25=0,
(x+y)²-10(x+y)+25=0
(x+y-5)²=0
x+y-5=0
x+y=5
∵x-y=2
∴x=3.5, y=1.5

Answer 2

x+y）(x+y-10)+25=0,且
x-y=2，
x=2+y
代入（x+y）(x+y-10)+25=0,得
（2+2y）（2+2y-10）+25=0
2+2y=5
y=3/2
x=7/3

Answer 3

(x+y）*(x+y-10)+25=0, (x+y)²-10(x+y)+25=0 (x+y-5)²=0
x+y=5 x-y=2
联立得x=7/2, y=3/2

Answer 4

我来帮您吧！
(x+y）(x+y-10)+25=0,
解： (x+y)²-10(x+y)+25=0
(x+y-5)²=0
x+y-5=0
x+y=5
∵x-y=2
∴x=3.5, y=1.5

Answer 5

x=y+2,代入（x+y）(x+y-10)+25=0,得：（2y+2）（2y-8）+25=0，解得：y=3/2，x=3/2+2=7/2

Answer 6

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