Question

求助因式分解

分解因式(a+1)^2+(b+1)+2ab-1
中间的是(b+1)^2

Answer 1

=a^2+2a+1+(b+1)^2+2ab-1
=a^2+2a(b+1)+(b+1)^2
=(a+b+1)^2

Answer 2

(a+1)^2+(b+1)+2ab-1
=a^2+2a+1+(b+1)^2+2ab-1
=a^2+2a(b+1)+(b+1)^2
=(a+b+1)^2

Answer 3

原式为：（a＋1）²＋（b＋1）²＋2ab－1
=a²＋2a＋1＋b²＋2b＋1＋2ab－1
=(a²＋2ab＋b²)＋(2a＋2b)＋1
=(a＋b)²＋2(a＋b)＋1
=(a＋b＋1)²

Answer 4

(a+1)^2+(b+1)+2ab-1 b+1加什么括号啊