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1/x-1/y=2 => (y-x)/xy=2, => y-x=2xy => x-y=-2xy
(2x-xy-2y)/(x+4xy-y)
={2(x-y)-xy}/{(x-y)+4xy}
=(-4xy-xy)/(-2xy+4xy)
=-5xy/2xy
=-5/2
(2x-xy-2y)/(x+4xy-y)
={2(x-y)-xy}/{(x-y)+4xy}
=(-4xy-xy)/(-2xy+4xy)
=-5xy/2xy
=-5/2
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