Question

-3x^2(2x^3+x^2-1)*(1/2x)要过程 (-1/3xy)^2*[xy(2x-y)-2x(xy-y^2)]要过程 谢谢

Answer 1

-3x^2(2x^3+x^2-1)*(1/2x)
=(-6x^5-3x^4+3x^2)*(1/2x)
=-3x^6-3/2x^5+3/2x^3

(-1/3xy)^2*[xy(2x-y)-2x(xy-y^2)]
=(1/9x²y²)*(2x²y-xy²-2x²y+2xy²)
=(1/9x²y²)*(xy²)
=1/9x^3y^4

Answer 2

-3x^2(2x^3+x^2-1)*(1/2x)
=(-3x/2)(2x^3+x^2-1)
=-3x^4-3x^3/2+3x/2
(-1/3xy)^2*[xy(2x-y)-2x(xy-y^2)]
= (-1/3xy)^2*[xy(2x-y)-2xy(x-y)]
= (-1/3xy)^2*xy(2x-y-2x+2y)
= (1/9x^2y^2)*xy^2
=1/9x