已知x+y=-4,xy=-12,求y+1/x+1+x+1/y+1 的值
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原式=(y+1)/(x+1)+(x+1)/(y+1)
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2x+2y+2]/[x+y+xy+1]
=[(x+y)²-2xy+2(x+y)+2]/[(x+y)+(xy)+1]
=[16-24+8+2]/[-4-12+1]
=-2/15
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2x+2y+2]/[x+y+xy+1]
=[(x+y)²-2xy+2(x+y)+2]/[(x+y)+(xy)+1]
=[16-24+8+2]/[-4-12+1]
=-2/15
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展开全部
y+1/x+1+x+1/y+1
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2(x+y)+2]/(x+y+xy+1)
=[(x+y)²+2(x+y)-2xy+2]/(x+y+xy+1)
=[(-4)²+2x(-4)-2x(-12)+2]/(-4-12+1)=-34/15
=[(y+1)²+(x+1)²]/[(x+1)(y+1)]
=[x²+y²+2(x+y)+2]/(x+y+xy+1)
=[(x+y)²+2(x+y)-2xy+2]/(x+y+xy+1)
=[(-4)²+2x(-4)-2x(-12)+2]/(-4-12+1)=-34/15
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