Question

已知2x-y=1/8,xy=2，求2x的四次方y的三次方-x的三次方y的四次方的值

Answer 1

解：原式=2x^4*y^3-x^3y^4
=x^3y^3(2x-y)
=2^3*8
=64

解：原式=2x^4y^3-x^3y^4
=(xy)^3(2x-y)
=2^3*1/8
=1

解：原式=2x(xy）的三次方-(xy）的三次方y
=(xy）的三次方×（2x-y)
=2的三次方×1/8
=1

nice

Answer 2

原式=2x(xy）的三次方-(xy）的三次方y
=(xy）的三次方×（2x-y)
=2的三次方×1/8
=1

Answer 3

解：2x^4y^3-x^3y^4
=(xy)^3(2x-y)
=2^3*1/8
=1