(x+y)× x^2/x^2-y^2 +y^2/y-x=?
1个回答
2012-03-04
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(x+y)x²/(x²-y²)+y²/(y-x)
=(x+y)x²/[(x+y)(x-y)]+y²/(y-x)
=x²/(x-y)+y²/(y-x)
=x²/(x-y)-y²/(x-y)
=(x²-y²)/(x-y)
=(x+y)(x-y)/(x-y)
=x+y
=(x+y)x²/[(x+y)(x-y)]+y²/(y-x)
=x²/(x-y)+y²/(y-x)
=x²/(x-y)-y²/(x-y)
=(x²-y²)/(x-y)
=(x+y)(x-y)/(x-y)
=x+y
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