求此电路题详细解答过程.
1个回答
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时间常数 t = R C = 5
用三要素法的通式:
Uc(τ) = Uc(∞) +((Uc(0+) - Uc(∞))e^(-t/τ)
= 10 + (0 - 10) e^(- 5/τ)
= 10 - 10 e^(- 5/τ)
I(τ) = I0 e^(-t/τ) ;I0 :初始电流。
= (10/5) e^(-5/τ)
, = 2 e^(-5/τ)
http://wenku.baidu.com/view/b48f0f4769eae009581bec81.html
用三要素法的通式:
Uc(τ) = Uc(∞) +((Uc(0+) - Uc(∞))e^(-t/τ)
= 10 + (0 - 10) e^(- 5/τ)
= 10 - 10 e^(- 5/τ)
I(τ) = I0 e^(-t/τ) ;I0 :初始电流。
= (10/5) e^(-5/τ)
, = 2 e^(-5/τ)
http://wenku.baidu.com/view/b48f0f4769eae009581bec81.html
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