无机化学一道小题
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1)ΔrGmθ = -2.303RTlogKθ= -2.303×8.314×298.15×log(4.9×10^16)= -95.279
2)ΔrSmθ = (ΔfHmθ-ΔrGmθ)/T = (-92.307+95.279)×10^3÷298.15=9.968
3)忽略掉T对於ΔfHmθ与ΔrSmθ的影响,则ΔrGm= -92.307 - 9.968÷10^3×700 = -99.2847
此时的log(K2θ/Kθ)=(ΔfHmθ/2.303R)*(T2-T1)/(T1*T2)= (-92.307÷2.303÷8.314)×(700-298.15)÷(700×298.15)
则K2θ=4.796×10^16
2)ΔrSmθ = (ΔfHmθ-ΔrGmθ)/T = (-92.307+95.279)×10^3÷298.15=9.968
3)忽略掉T对於ΔfHmθ与ΔrSmθ的影响,则ΔrGm= -92.307 - 9.968÷10^3×700 = -99.2847
此时的log(K2θ/Kθ)=(ΔfHmθ/2.303R)*(T2-T1)/(T1*T2)= (-92.307÷2.303÷8.314)×(700-298.15)÷(700×298.15)
则K2θ=4.796×10^16
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