分解因式: (x-2)+(2-y)+(y-x)= 3x+5xy-2y+x+9y-4= 4
分解因式:(x-2)+(2-y)+(y-x)=3x+5xy-2y+x+9y-4=4(x-y+1)+y(y-2x)=a-5ab+6ab=...
分解因式:
(x-2)+(2-y)+(y-x)=
3x+5xy-2y+x+9y-4=
4(x-y+1)+y(y-2x)=
a-5ab+6ab= 展开
(x-2)+(2-y)+(y-x)=
3x+5xy-2y+x+9y-4=
4(x-y+1)+y(y-2x)=
a-5ab+6ab= 展开
3个回答
2014-09-04
展开全部
(x-2)^3+(2-y)^3+(y-x)^3
=(x-2)^3+(2-y)^3-(x-y)^3
=(x-2)^3+(2-y)^3-(x-2+2-y)^3
=(x-2)^3+(2-y)^3-(x-2+2-y)^3
a=x-2,b=2-y
则
=(a+b)^3-(a+b)^3+3a^2*b+3a*b^2
=3ab(a+b)
=3(x-2)(2-y)(x-2+2-y)
=3(x-2)(2-y)(x-y)
=(x-2)^3+(2-y)^3-(x-y)^3
=(x-2)^3+(2-y)^3-(x-2+2-y)^3
=(x-2)^3+(2-y)^3-(x-2+2-y)^3
a=x-2,b=2-y
则
=(a+b)^3-(a+b)^3+3a^2*b+3a*b^2
=3ab(a+b)
=3(x-2)(2-y)(x-2+2-y)
=3(x-2)(2-y)(x-y)
更多追问追答
追答
3x+5xy-2y+x+9y-4
=(3x-y)(x+2y)+x+9y-4
=(3x-y)(x+2y)-(3x-y)+4x+8y-4
=(3x-y)(x+2y-1)+4(x+2y-1)
=(3x-y+4)(x+2y-1)
=4x-4y+4+y-2xy
=(y-4y+4)+4x-2xy
=(y-2)+2x(2-y)
=(2-y)+2x(2-y)
=(2-y)(2x+2-y)
=(y-2)(y-2x-2)
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怎么看了就头疼呢
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