Question

求因式分解。

Answer 1

原式=(x-2y)(x-y)-2(x-y)-x+2y+2
=(x-2y-2)(x-y)-(x-2y-2)
=(x-2y-2)(x-y-1)

请好评

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Answer 2

解：x²-3xy+2y²-3x+4y+2
=(x-y)(x-2y)-2x+2y-x+2y+2
=(x-y)(x-2y)-2(x-y)-(x-2y-2)
=(x-y)(x-2y-2)-(x-2y-2)
=(x-2y-2)(x-y-1)

Answer 3

x²-3xy+2y²-3x+4y+2
=(x-2y)(x-y)-x-2x+2y+2y+2
=(x-2y)(x-y)-x+2y+2y-2x+2
=(x-2y)(x-y)-(x-2y)-2(x-y-1)
=(x-2y)(x-y-1)-2(x-y-1)
=(x-y-1)(x-2y-2)

Answer 4

(x-y-1)(x-2y-2)