Question

(2a-1)的平方乘以(2a+1)的平方

Answer 1

(2a-1)²*(2a+1)²
=[(2a-1)(2a+1]²
=[(2a)²-1²]²
=(4a²-1)²
=16a的4次方-4a²+1

追问

(3a-2b)的平方-（3a+2b）的平方

追答

(3a-2b)²-（3a+2b）²
=[(3a-2b)+(3a+2b)] [(3a-2b)-(3a+2b)]
=6a*(-4b)
=-24ab

追问

(2a-3)(-2a+3)

追答

(2a-3)(-2a+3)
= - (2a-3)(2a-3)
= -(2a-3)²
=-4a²+12a-9

Answer 2

(2a-1)²(2a+1)²
=(2a-1)(2a-1)(2a+1)(2a+1)
=(2a-1)(2a+1)(2a-1)(2a+1)
=(4a²-1)(4a²-1)
=(4a^2-1)²
=16a²-8a+1

追问

3a-2b)的平方-（3a+2b）的平方

追答

(3a-2b)的平方-（3a+2b）的平方
=(3a-2b+3a+2b)(3a-2b-3a-2b)
=6a(-4b)
=-24ab

Answer 3

（2a-1)^（2）（2a+1)^2=[(2a-1)(2a+1)]^2=(4a^2-1)^2=16a^4-8a^2+1

Answer 4

(2a-1)²(2a+1)²
=[(2a-1)(2a+1)]²
=(4a²-1)²
=16a的四次方-8a²+1

Answer 5

（4a的平方-1）的平方